**1996 Leaving Certificate
Ordinary Level**

A train,starting from rest,
is uniformly accelerated to reach a speed of v m/s in 100s over 500m.

The speed of v m/s is maintained
for a further 1500 m and the train is then brought to rest in the next
250 m under uniform retardation.

(i) Find the value of v

(ii) Find the acceleration
and retardation

(iii) Find the total time

(iv) Draw an accurate velocity-time
graph.

Area of left triangle =

Acceleration =

Area of rectangle = 10X = 1500 X = 150s

Area of right triangle =

Total Time = 100 150 50 = 300 s

Retardation =