1996 Leaving Certificate Ordinary Level
A train,starting from rest,
is uniformly accelerated to reach a speed of v m/s in 100s over 500m.
The speed of v m/s is maintained for a further 1500 m and the train is then brought to rest in the next 250 m under uniform retardation.
(i) Find the value of v
(ii) Find the acceleration and retardation
(iii) Find the total time
(iv) Draw an accurate velocity-time graph.
Area of left triangle =
Area of rectangle = 10X = 1500 X = 150s
Area of right triangle =
Total Time = 100 150 50 = 300 s